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单片机驱动16X192点阵程序及proteus仿真

发布时间:2020-08-27 发布时间:
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下面是16X192点阵取模软件的设置截图
 
下面是16X192点阵的仿真原理图:

单片机源程序:

#include

sbit ST=P3^5;

sbit E1=P3^4;

sbit MR=P3^7;

char cashe[12];

char code wd[12][16]={



{0xFF,0xC0,0xFE,0xFE,0xFE,0xFE,0x80,0xFE,0xFD,0xFD,0xFB,0xF7,0xEF,0xDF,0x3F,0xFF},

{0xFF,0x03,0xFF,0xFF,0xFF,0xFF,0x01,0x7F,0x7F,0x7F,0x7F,0x7F,0x7D,0x7D,0x81,0xFF},/*"无",0*/

/* (16 X 16 , 宋体 )*/


{0xDF,0xDF,0xDF,0xCF,0x57,0x58,0x5F,0xDF,0xDE,0xDE,0xDE,0xDD,0xDD,0xDB,0xDB,0xD7},

{0x7F,0x6F,0x73,0x77,0x7F,0x01,0x5F,0x5F,0xDF,0xDF,0xDF,0xDF,0xDD,0xDD,0xE1,0xFF},/*"忧",1*/

/* (16 X 16 , 宋体 )*/


{0xFE,0xFE,0xFE,0xC0,0xDE,0xDE,0xC0,0xDE,0xDE,0xDE,0xC0,0xDE,0xFE,0xFE,0xFF,0xFF},

{0xFF,0xFF,0xFF,0x07,0xF7,0xF7,0x07,0xF7,0xF7,0xF7,0x07,0xF7,0xFD,0xFD,0x01,0xFF},/*"电",2*/

/* (16 X 16 , 宋体 )*/


{0xFF,0xC0,0xFF,0xFF,0xFF,0xFE,0xFE,0xFE,0x00,0xFE,0xFE,0xFE,0xFE,0xFE,0xFA,0xFD},

{0xFF,0x0F,0xDF,0xBF,0x7F,0xFF,0xFF,0xFB,0x01,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF},/*"子",3*/

/* (16 X 16 , 宋体 )*/


{0xFF,0x83,0xBB,0xAB,0xAA,0xAA,0xA9,0xAB,0xAB,0xAA,0xEE,0xD7,0xDB,0xBB,0x7F,0xFF},

{0x7F,0x3F,0x7F,0x01,0xFD,0xFD,0xBD,0xBD,0x5D,0xED,0x05,0xED,0xFD,0xFD,0xEB,0xF7},/*"购",4*/

/* (16 X 16 , 宋体 )*/


{0xEF,0xEF,0xAF,0xAE,0x82,0xAD,0x6B,0xEB,0xE6,0xCD,0x2B,0xEF,0xEE,0xED,0xEB,0xFF},

{0x7F,0x7F,0x7F,0x03,0xAB,0xAB,0x6B,0x6B,0xDB,0xDB,0xBB,0x7B,0xFB,0xFB,0xD7,0xEF},/*"物",5*/

/* (16 X 16 , 宋体 )*/




};



void del(int i)//============================//延时程序

{while(i--);}


aline()        ////=======================发送一行的显示程序

{

char i=0;

TI=0;

for(i=0;i<12;i++)

{SBUF=cashe[i];while(~TI);TI=0;} //将缓存中的信息转存入595的存储器中,到此不显示

}




main()

{

int m=0,n=0;

        TI=0;

        SM0=0;

        SM1=0;

E1=0;

while(1)

for(m=0;m<16;m++)      //共有16行  循环16次显示这16行  串行的595送出行的数据

        {                                        //由74hc154选中要显示的行


        for(n=0;n<12;n++)         //这个for循环用来向缓存数组中装载要显示的内容

                {cashe[11-n]=wd[n][m];}  //将第m个字的第n行信息装载  ,因为595串接 数据第一个进去的会在最后一个595中,最后进去的会在第一个595中

    aline();     //将缓存中的一行信息载入595缓存中

        ST=0;ST=1; //595产生上升沿 输出595锁存的数据

        P2=m;  //选中要显示的行输出数据

      

        del(100);//延时一段时间,以造成视觉暂存效应


          }


}


关键字:单片机  驱动16X192点阵  proteus仿真 

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